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Contoh: $\ce{2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)}$, \(\dfrac12\), \[\sum_{n=1}^\infty x^n\], dll
$\ce{2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)}$ $\ce{NH3(aq) + HCl (aq) → NH4Cl(aq) }$ (Kb $\ce{NH4OH \ = \ 1,0 × 10^{-5}}$) pecahan $\frac{25}{50}$ = $\dfrac12$

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